If it's not what You are looking for type in the equation solver your own equation and let us solve it.
4x^2+32x-8=0
a = 4; b = 32; c = -8;
Δ = b2-4ac
Δ = 322-4·4·(-8)
Δ = 1152
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{1152}=\sqrt{576*2}=\sqrt{576}*\sqrt{2}=24\sqrt{2}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(32)-24\sqrt{2}}{2*4}=\frac{-32-24\sqrt{2}}{8} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(32)+24\sqrt{2}}{2*4}=\frac{-32+24\sqrt{2}}{8} $
| X/17=10/2,x= | | X/17=10/2x= | | 3x+25/3x=10 | | 79x=55.68 | | X2+3x=12-2x-X2 | | (3p+5)X3=9p+15 | | 2y+2+3y+1=48 | | -169-9x=2x+161 | | 38c−2=32c−12 | | 400p+500(1-p)=600p+400(1-p) | | 2^x-3x-6=0 | | 6x-8x*x*x=2 | | 9x-45=6(x-8) | | 3^5x-10=243 | | 16x2=9 | | (16-2x)(10-2x)=80 | | -2/5=-2/3w-1/2 | | 10r-r^2=25 | | 4k+5/3=2k+7 | | -m-10=1 | | -7-16m=-16m-7 | | -8k-5=-2k-6k-5 | | 500q+700(1-q)=800q+500(1-q) | | -6p-9=-7p | | 3x-1=2((x-1) | | 7+2t-3t=-5-t | | -4c=-2c-8 | | -10-10u=-u-10-9u | | 600p+400(1-p)=400p+500(1-p) | | 4v+9=4v-2 | | 5(u-1)-3=-3(-8u+4)-3u | | -34=4(y-7)-7y |